# Line slope calculator 7x+3y=79

**Straight line given by points A[7; 10] and B[10; 3]**

## Calculation:

**Slope-intercept form of line:**y = -2.3333x+26.3333

**Canonical form of the line equation:**7x+3y-79 = 0

**Parametric form of the line equation:**

x = 3t+7

y = -7t+10 ; t ∈ R

**Slope:**m = -2.3333

**Slope angle of line: φ =**-66°48'5″ = -1.1659 rad

**X intercept:**x

_{0}= 11.2857

**Y intercept:**y

_{0}= q = 26.3333

**Distance line from the origin:**d

_{0}= 10.3732

**The length of the segment AB: |AB| =**7.6158

**Vector: AB =**(3; -7)

**Normal vector: n =**(7; 3)

**Midpoint of the segment AB: M =**[8.5; 6.5]

**Perpendicular Bisector equation:**3x-7y+20 = 0

**Vector OA = (7; 10) ; |OA| = 12.2066**

**Vector OB = (10; 3) ; |OB| = 10.4403**

**Scalar product OA .OB = 100**

**Angle ∠ AOB = 38°18'31″ = 0.6686 rad**