# Line slope calculator x-4y=-19

**Straight line given by points A[1; 5] and B[5; 6]**

## Calculation:

**Slope-intercept form of line:**y = 0.25x+4.75

**Canonical form of the line equation:**x-4y+19 = 0

**Parametric form of the line equation:**

x = 4t+1

y = t+5 ; t ∈ R

**Slope:**m = 0.25

**Slope angle of line: φ =**14°2'10″ = 0.245 rad

**X intercept:**x

_{0}= -19

**Y intercept:**y

_{0}= q = 4.75

**Distance line from the origin:**d

_{0}= 4.6082

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(4; 1)

**Normal vector: n =**(1; -4)

**Midpoint of the segment AB: M =**[3; 5.5]

**Perpendicular Bisector equation:**4x+y-17.5 = 0

**Vector OA = (1; 5) ; |OA| = 5.099**

**Vector OB = (5; 6) ; |OB| = 7.8102**

**Scalar product OA .OB = 35**

**Angle ∠ AOB = 28°29'44″ = 0.4973 rad**