# Line slope calculator 9x-y=53

**Straight line given by points A[6; 1] and B[7; 10]**

## Calculation:

**Slope-intercept form of line:**y = 9x-53

**Canonical form of the line equation:**9x-y-53 = 0

**Parametric form of the line equation:**

x = t+6

y = 9t+1 ; t ∈ R

**Slope:**m = 9

**Slope angle of line: φ =**83°39'35″ = 1.4601 rad

**X intercept:**x

_{0}= 5.8889

**Y intercept:**y

_{0}= q = -53

**Distance line from the origin:**d

_{0}= 5.8529

**The length of the segment AB: |AB| =**9.0554

**Vector: AB =**(1; 9)

**Normal vector: n =**(9; -1)

**Midpoint of the segment AB: M =**[6.5; 5.5]

**Perpendicular Bisector equation:**x+9y-56 = 0

**Vector OA = (6; 1) ; |OA| = 6.0828**

**Vector OB = (7; 10) ; |OB| = 12.2066**

**Scalar product OA .OB = 52**

**Angle ∠ AOB = 45°32'44″ = 0.7949 rad**